Igor Kudrin
fa4a3a18db
The 'ValueObject::AddressOf()' method assumes that the address of a value object cannot change, so when it is calculated once, it does not need to be updated afterwards. However, this is not the case if the 'ValueObject' is a dependent object obtained by calling 'Dereference()' of another 'ValueObject'. If the latter object is changed, the dependent value object should return a new address from the 'AddressOf()' method to reflect the change. (cherry picked from commit 320164daab4148e3372f6756caaa67882e24a91f)
32 lines
397 B
C
32 lines
397 B
C
int test1() {
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int a = 5;
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int b = 7;
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int *p = &a;
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p = &b; // break here 1
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return *p;
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}
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char test2() {
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struct S {
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char a;
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char b;
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};
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struct S arr[2] = {{'a', 'b'}, {'c', 'd'}};
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struct S *p = arr;
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++p; // break here 2
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return p->b;
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}
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int test3() {
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int a = 5;
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int b = 7;
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return a + b; // break here 3
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}
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int main() {
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test1();
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test2();
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test3();
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return 0;
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}
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