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sfc/slicer.py: print Z position of layer being processes

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Werner Almesberger 2015-09-28 18:14:43 -03:00
parent 346899c34c
commit 5c6a81033f
1 changed files with 1 additions and 0 deletions
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sfc/slicer.py
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@ -222,6 +222,7 @@ if height is not None and height < 0 and z_levels[-1] > height:
for i in range(0, len(z_levels)): for i in range(0, len(z_levels)):
next_z = z_levels[i] next_z = z_levels[i]
print >>sys.stderr, "next_z = ", next_z
wires = shape.slice(Base.Vector(0, 0, 1), next_z + epsilon) wires = shape.slice(Base.Vector(0, 0, 1), next_z + epsilon)
if i == len(z_levels) - 1: if i == len(z_levels) - 1:
next_z += end next_z += end