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eeshow/sch-parse.c (parse_line): use sub-sheet name as title, instead of title

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In Anelok, all sheets have the same title, but different sub-sheet names.
So this is probably a more reliable heuristic.
This commit is contained in:
Werner Almesberger 2016-08-11 02:49:40 -03:00
parent 7cc2142e83
commit 82635e8a41
1 changed files with 7 additions and 2 deletions
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9
eeshow/sch-parse.c
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@ -304,7 +304,7 @@ static struct sheet *new_sheet(struct sch_ctx *ctx)
static bool parse_line(const struct file *file, void *user, const char *line); static bool parse_line(const struct file *file, void *user, const char *line);
static const struct sheet *recurse_sheet(struct sch_ctx *ctx, static struct sheet *recurse_sheet(struct sch_ctx *ctx,
const struct file *related) const struct file *related)
{ {
const char *name = ctx->obj.u.sheet.file; const char *name = ctx->obj.u.sheet.file;
@ -509,11 +509,16 @@ static bool parse_line(const struct file *file, void *user, const char *line)
sheet_obj = submit_obj(ctx, sch_obj_sheet); sheet_obj = submit_obj(ctx, sch_obj_sheet);
if (ctx->recurse) { if (ctx->recurse) {
const struct sheet *sheet; struct sheet *sheet;
sheet = recurse_sheet(ctx, file); sheet = recurse_sheet(ctx, file);
if (!sheet) if (!sheet)
return 0; return 0;
if (sheet_obj->u.sheet.name) {
free((char *) sheet->title);
sheet->title =
stralloc(sheet_obj->u.sheet.name);
}
sheet_obj->u.sheet.sheet = sheet; sheet_obj->u.sheet.sheet = sheet;
} else { } else {
sheet_obj->u.sheet.sheet = NULL; sheet_obj->u.sheet.sheet = NULL;